2^2x+3=1/8

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Solution for 2^2x+3=1/8 equation:



2^2x+3=1/8
We move all terms to the left:
2^2x+3-(1/8)=0
We add all the numbers together, and all the variables
2^2x+3-(+1/8)=0
We get rid of parentheses
2^2x+3-1/8=0
We multiply all the terms by the denominator
2^2x*8-1+3*8=0
We add all the numbers together, and all the variables
2^2x*8+23=0
Wy multiply elements
16x^2+23=0
a = 16; b = 0; c = +23;
Δ = b2-4ac
Δ = 02-4·16·23
Δ = -1472
Delta is less than zero, so there is no solution for the equation

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